7x^2+14x-16=8x^2+6x

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Solution for 7x^2+14x-16=8x^2+6x equation:



7x^2+14x-16=8x^2+6x
We move all terms to the left:
7x^2+14x-16-(8x^2+6x)=0
We get rid of parentheses
7x^2-8x^2+14x-6x-16=0
We add all the numbers together, and all the variables
-1x^2+8x-16=0
a = -1; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-2}=+4$

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